Daffodil International University
Faculties and Departments => Faculty Sections => Departments => Topic started by: jas_fluidm on September 22, 2013, 01:23:57 PM
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When positive integer x is divided by 5, the remainder is 3; and when x is divided by 7, the remainder is 4. When positive integer y is divided by 5, the remainder is 3; and when y is divided by 7, the remainder is 4. If x > y, which of the following must be a factor of x - y?
ans: 35
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want more posts.
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Nice and enjoying..............
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An elementary school has 6 grade levels: Kindergarten, 1st grade, 2nd grade, 3rd grade, 4th grade, and 5th grade. Each grade has 2 homeroom classes, except for the 5th grade, which has 3 homeroom classes. If the homeroom class sizes in Kindergarten, 1st grade, and 2nd grade are 2/3 the size of the homeroom class sizes for the other grades, how many students attend the school if the fifth grade has 108 total students?
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Explanation: Half of the grade levels, the 3rd, 4th, and 5th grades, have a homeroom class size 3/2 the size of the other grades. With 3 homeroom classes instead of 2, the 5th grade has 3/2 the students as the 3rd and 4th grades. This means that the fifth grade has 9/4 as many students as 1st and 2nd grades, as well as the Kindergarten level. Each of the grades K-2 will have populations of 48 students: 108(4/9); each of the grades 3-4 will have populations of 72: 108(2/3), giving us a total of 396 (3[48] + 2[72] + 108 = 12[12] + 12[12] + 9[12] = 33[12]).
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Post another one and I desire to build up my ken on math.
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wow! interesting and enjoying! want more posts.. thank u
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please try ...
Take 9 from 6, 10 from 9, 50 from 40 and leave 6.
How Come ??
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SIX – 9 (IX) = S
9 (IX) – 10 (X) = I
40 (XL) – 50 (L) = X
===>SIX
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jashim sir i dont understand your problem,plz delineate
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Sir it's simple puzzle but brain teasing
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thanks. I would like to try
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Excellent post
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thanks Nafi Bhai
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good one ...
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Nice post. Thanks for sharing.