Daffodil International University

Science & Information Technology => Science Discussion Forum => Topic started by: jas_fluidm on March 08, 2012, 11:03:06 AM

Title: Simple basic math problem
Post by: jas_fluidm on March 08, 2012, 11:03:06 AM

a manager is forming a 6-person team to work on a certain project . from the 11 candidates available for the team , the manager has already chosen 3 to be on the team , in selecting the other 3 team members , how many different combinations of 3 of the remaining candidates does the manager have to choose from ?

answer:
There are only 8 people left to choose from, so 8C3 = 8! / (3! * 5!) = (8*7*6*5*4*3*2*1)/(3*2*1*5*4*3*2*1) = (8*7*6)/(3*2*1) = 56

Title: Re: Simple basic math problem
Post by: arefin on March 09, 2012, 11:39:03 AM

Thanks

Title: Re: Simple basic math problem
Post by: Sima on March 13, 2012, 02:17:28 PM

Truly basic...

Title: Re: Simple basic math problem
Post by: tasnuva on March 14, 2012, 01:47:16 PM

Thanks for sharing..