# Daffodil International University

## Faculties and Departments => Faculty Sections => Departments => Topic started by: jas_fluidm on September 22, 2013, 01:23:57 PM

Title: Re: math problem of the day(another)
Post by: jas_fluidm on September 22, 2013, 01:23:57 PM
When positive integer x is divided by 5, the remainder is 3; and when x is divided by 7, the remainder is 4. When positive integer y is divided by 5, the remainder is 3; and when y is divided by 7, the remainder is 4. If x > y, which of the following must be a factor of x - y?
ans: 35
Title: Re: math problem of the day(another)
Post by: Khandoker Samaher Salem on September 23, 2013, 06:50:32 PM
Title: Re: math problem of the day(another)
Post by: Anuz on November 17, 2013, 12:29:32 PM
Nice and enjoying..............
Title: Re: math problem of the day(another)
Post by: jas_fluidm on April 07, 2014, 07:23:35 PM
Title: Re: math problem of the day(another)
Post by: jas_fluidm on April 07, 2014, 07:25:40 PM
Explanation: Half of the grade levels, the 3rd, 4th, and 5th grades, have a homeroom class size 3/2 the size of the other grades. With 3 homeroom classes instead of 2, the 5th grade has 3/2 the students as the 3rd and 4th grades. This means that the fifth grade has 9/4 as many students as 1st and 2nd grades, as well as the Kindergarten level. Each of the grades K-2 will have populations of 48 students: 108(4/9); each of the grades 3-4 will have populations of 72: 108(2/3), giving us a total of 396 (3[48] + 2[72] + 108 = 12[12] + 12[12] + 9[12] = 33[12]).
Title: Re: math problem of the day(another)
Post by: Md. Fouad Hossain Sarker on April 08, 2014, 07:44:15 PM
Post another one and I desire to build up my ken on math.
Title: Re: math problem of the day(another)
Post by: sayma on April 09, 2014, 10:29:11 AM
wow! interesting and enjoying! want more posts.. thank u
Title: Re: math problem of the day(another)
Post by: jas_fluidm on July 12, 2014, 05:34:40 PM

Take 9 from 6, 10 from 9, 50 from 40 and leave 6.

How Come ??
Title: Re: math problem of the day(another)
Post by: jas_fluidm on July 12, 2014, 05:51:51 PM
SIX – 9 (IX) = S
9 (IX) – 10 (X) = I
40 (XL) – 50 (L) = X
===>SIX
Title: Re: math problem of the day(another)
Post by: habib.cse on July 14, 2014, 08:36:06 PM
jashim sir i dont understand your problem,plz delineate
Title: Re: math problem of the day(another)
Post by: jas_fluidm on July 14, 2014, 08:39:21 PM
Sir it's simple puzzle but brain teasing
Title: Re: math problem of the day(another)
Post by: habib.cse on July 14, 2014, 11:51:20 PM
thanks. I would like to try
Title: Re: math problem of the day(another)
Post by: kwnafi on July 16, 2014, 10:09:52 PM
Excellent post
Title: Re: math problem of the day(another)
Post by: jas_fluidm on July 21, 2014, 05:29:16 PM
thanks Nafi Bhai
Title: Re: math problem of the day(another)
Post by: mahmud_eee on August 07, 2014, 04:33:21 PM
good one ...
Title: Re: math problem of the day(another)
Post by: Kazi Taufiqur Rahman on August 12, 2014, 08:21:13 PM
Nice post. Thanks for sharing.