Re: math problem of the day(another)

### Author Topic: Re: math problem of the day(another)  (Read 1850 times)

#### jas_fluidm

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##### Re: math problem of the day(another)
« on: September 22, 2013, 01:23:57 PM »
When positive integer x is divided by 5, the remainder is 3; and when x is divided by 7, the remainder is 4. When positive integer y is divided by 5, the remainder is 3; and when y is divided by 7, the remainder is 4. If x > y, which of the following must be a factor of x - y?
ans: 35

#### Khandoker Samaher Salem

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##### Re: math problem of the day(another)
« Reply #1 on: September 23, 2013, 06:50:32 PM »
Khandoker Samaher Salem
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Dept. of Textile Engineering, FE
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#### Anuz

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##### Re: math problem of the day(another)
« Reply #2 on: November 17, 2013, 12:29:32 PM »
Nice and enjoying..............
Anuz Kumar Chakrabarty
Assistant Professor
Department of General Educational Development
Faculty of Science and Information Technology
Daffodil International University

#### jas_fluidm

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##### Re: math problem of the day(another)
« Reply #3 on: April 07, 2014, 07:23:35 PM »
An elementary school has 6 grade levels: Kindergarten, 1st grade, 2nd grade, 3rd grade, 4th grade, and 5th grade. Each grade has 2 homeroom classes, except for the 5th grade, which has 3 homeroom classes. If the homeroom class sizes in Kindergarten, 1st grade, and 2nd grade are 2/3 the size of the homeroom class sizes for the other grades, how many students attend the school if the fifth grade has 108 total students?

#### jas_fluidm

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##### Re: math problem of the day(another)
« Reply #4 on: April 07, 2014, 07:25:40 PM »
Explanation: Half of the grade levels, the 3rd, 4th, and 5th grades, have a homeroom class size 3/2 the size of the other grades. With 3 homeroom classes instead of 2, the 5th grade has 3/2 the students as the 3rd and 4th grades. This means that the fifth grade has 9/4 as many students as 1st and 2nd grades, as well as the Kindergarten level. Each of the grades K-2 will have populations of 48 students: 108(4/9); each of the grades 3-4 will have populations of 72: 108(2/3), giving us a total of 396 (3[48] + 2[72] + 108 = 12[12] + 12[12] + 9[12] = 33[12]).

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##### Re: math problem of the day(another)
« Reply #5 on: April 08, 2014, 07:44:15 PM »
Post another one and I desire to build up my ken on math.
Department of Development Studies
Faculty of Humanities and Social Sciences
Daffodil International University
Dhaka-1207

#### sayma

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##### Re: math problem of the day(another)
« Reply #6 on: April 09, 2014, 10:29:11 AM »

#### jas_fluidm

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##### Re: math problem of the day(another)
« Reply #7 on: July 12, 2014, 05:34:40 PM »

Take 9 from 6, 10 from 9, 50 from 40 and leave 6.

How Come ??
« Last Edit: July 12, 2014, 05:37:09 PM by jas_fluidm »

#### jas_fluidm

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##### Re: math problem of the day(another)
« Reply #8 on: July 12, 2014, 05:51:51 PM »
SIX – 9 (IX) = S
9 (IX) – 10 (X) = I
40 (XL) – 50 (L) = X
===>SIX

#### habib.cse

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##### Re: math problem of the day(another)
« Reply #9 on: July 14, 2014, 08:36:06 PM »
jashim sir i dont understand your problem,plz delineate

#### jas_fluidm

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##### Re: math problem of the day(another)
« Reply #10 on: July 14, 2014, 08:39:21 PM »
Sir it's simple puzzle but brain teasing

#### habib.cse

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##### Re: math problem of the day(another)
« Reply #11 on: July 14, 2014, 11:51:20 PM »
thanks. I would like to try

#### kwnafi

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##### Re: math problem of the day(another)
« Reply #12 on: July 16, 2014, 10:09:52 PM »
Excellent post
Kawser Wazed Nafi
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Daffodil International University
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#### jas_fluidm

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##### Re: math problem of the day(another)
« Reply #13 on: July 21, 2014, 05:29:16 PM »
thanks Nafi Bhai

#### mahmud_eee

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##### Re: math problem of the day(another)
« Reply #14 on: August 07, 2014, 04:33:21 PM »
good one ...
Md. Mahmudur Rahman
Assistant Professor, EEE
FE, DIU